Infix to Prefix Conversion
Prefix, Infix, Postfix Conversion Problems DSA practice problem on Onlearn.
Difficulty: medium.
Topics: Converting Infix Expressions to Prefix Expressions, Stack, String Manipulation, Operator Precedence, Time Complexity, Space Complexity, Algorithm, string manipulation, expression parsing, expression notation, stack, general programming, time complexity analysis, Infix, Prefix, Postfix Notations.
Infix to Prefix Conversion Given an infix expression, your task is to convert it into its equivalent prefix expression. Input Specification The input will be a string representing a valid infix expression. It will consist of lowercase English letters (operands) and the operators +, , , /. Parentheses ( and ) may also be present. Output Specification Return a string representing the prefix expression. Constraints The input string will contain only lowercase English letters, +, , , /, ( and ). The expression will be a valid infix expression. Sample Test Cases Example 1: Input: Output: Explanation: The infix expression x+y z/w+u is converted to its prefix equivalent ++x/ yzwu. Example 2: Input: Output: Explanation: The infix expression a+b is converted to its prefix equivalent +ab.